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國一下數學求解!! 急~~:

Jun 10th 2013, 20:19

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Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決

國一下數學求解!! 急~~

Jun 8th 2013, 12:31

(1)通過原點表示x=0，將x代入f(x)即f(0) = (a+2)*0 + b = 0 => b = 0
(2)若f(x)為常數函數，即其非常數項的係數皆為零，在本例中就是x的係數(a+2)為零，也就是(a+2) = 0，得出的解即a = -2
(3)f(x)為一次函數，即其一次項的係數不為零，常數項任意，在本例中就是x的係數(a+2)不為零，而不為零的條件，就是為零的條件以外的所有條件，在本例中就是a勿能等於-2

以上是我個人見解

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